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Permutrix
the game based on the VMPC one-way function
playing instructions step by step:
The purpose of the game is to fill the table with numbers. This is an example Permutrix:
And this is how it looks done:
- numbers in columns B and C are the same.
- numbers in columns D and E differ by 1.
- the pair of numbers repeats in all three blocks.
Permutrix rules:
Fill each column of the table with different numbers from 1 to 6
and this way form 6 pairs of numbers. A pair is two numbers lying side by side in one block.
Put each pair in the table 3 times, each time in a different block.
The order of numbers is important, e.g.
and
are different pairs.
Additionally:
1. Numbers lying side by side in columns B and C are the same. E.g.
2. Numbers lying side by side in columns D and Ediffer by 1. E.g. The number greater by 1 in column E. An exception in columns D and E:
Let's solve the above Permutrix together to better understand the rules.
The empty Permutrix looks like this:
Step 1.
Newly entered numbers in a given step with be red.
Numbers lying side by side in columns B and C are the same. In column C there is a 3 so in column B
side by side we can enter also 3.
Numbers lying side by side in columns D and E differ by 1. In column D there is a 1 so in column E
side by side we can enter 2.
Step 2.
We can see numbers 1 and 3 lying side by side in one block (the AB block). So they are a pair.
We can remember that each pair must appear in the table 3 times - once in each block.
We can see a 3 in block EF and that it fits to our 1|3 pair. Therefore we can
enter 1 next to that 3. This way we already have two blocks where the 1|3 pair appears.
Step 3.
Numbers lying side by side in columns D and E differ by 1. There is a 1 in column E. 1-1=0
and while we can only use numbers from 1 to 6 then instead of 0 we rewind back to 6 in column D.
This is the exceptional situation where numbers 6|1 lie side by side in columns D and E.
Step 4.
We can see numbers 2 and 1 lying side by side in one block (the EF block). So they are a pair.
Each pair must appear once in each block. We can fit the 2|1 pair in both the AB and CD blocks.
This way the 2|1 pair already appears in all three blocks!
Step 5.
Numbers lying side by side in columns B and C are the same. In column B there is a 1 so in column B
side by side we can enter also 1. And similarly number 2 from column C can be copied to column B side by side.
Step 6.
We can see that a 1 appeared in column B so this is the place where we can enter the 1|3 pair which already
appears in blocks AB and EF.
Step 7.
We can see the 5|2 pair in block AB. Because there is a 2 in column F, we can fit this pair there - in the EF block.
Step 8.
Numbers lying side by side in columns D and E differ by 1. In column D there is a 3, so side by side in E
there will be 4. In E we can see a 5 so in D side by side we will have a 4.
Step 9.
We can see the 4|6 pair in block EF. We can fit this pair in both the AB and CD blocks.
Step 10.
Numbers lying side by side in columns B and C are the same. We can copy the 6 from column B to C
and the 4 from column C to B.
Step 11.
We can see a new pair 6|4 which already appears in two blocks. We can also fit it to the third EF block.
Step 12.
In column E there is a 6 so side by side in D there will be a number smaller by one, a 5.
Step 13.
We can see a new pair 3|5 in block CD. It fits to two other blocks.
Step 14.
We copy number 5 from column B to C and to column D we enter number 2 which is smaller by one than
number 3 side by side in column E.
Copyright (c) Bartosz Zoltak, OHTON EXPO. All rights reserved.
This game is protected by copyright law.
Copying and publishing any part of this document and publishing games
based on analogous rules without the author's consent is forbidden.
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